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README.md

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@@ -67,9 +67,9 @@ Note that some Normaliz output types must be specially encoded for python. Our H
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[[1], [1, 1], 0]
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to be read as follows: [1] is the numerator polynomial, [1,1] is the vector of exponents of t that occur in the denominator, which is (1-t)(1-t) in our case, and 0 is the shift. So the Hilbert series is given by the rational function 1/(1-t)(1-t). (Aoso see ee [this introduction](doc/PyNormaliz_Tutorial.pdf).)
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to be read as follows: [1] is the numerator polynomial, [1,1] is the vector of exponents of t that occur in the denominator, which is (1-t)(1-t) in our case, and 0 is the shift. So the Hilbert series is given by the rational function 1/(1-t)(1-t). (Also see [this introduction](doc/PyNormaliz_Tutorial.pdf).)
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One can also compute several data simultaneously and specify options ("PrimalMode" only added as an example, not because ot is particularly useful here):
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One can also compute several data simultaneously and specify options ("PrimalMode" only added as an example, not because it is particularly useful here):
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C.Compute("LatticePoints", "Volume", "PrimalMode")
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C2 = Cone(cone=[[1,1],[1,3]])
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intersection(C1,C2).ExtremeRays()
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yeilds the result
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yields the result
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[[1, 1], [1, 2]]
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